How do you complete the square when 'a' is not 1?

3 years ago

1 Reply

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Anais Green

1 Answer

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Factorise by taking a outside the brackets

So you start with y = ax^2 + bx + c

Factorise to get y = a [ x^2 + (b/a)x + c/a ]

Then complete the square for the bit inside the square brackets

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